Numbers Aptitude Test Questions(Mcq)
All Questions Answers are Given Below Check it
1.The Unit Digit in the Produt (784×618×917×463)
All Questions Answers are Given Below Check it
1.The Unit Digit in the Produt (784×618×917×463)
-
2
3
5
4
2. 9587-X=7429-4358 then X=?
-
5011
6516
6511
6173
3.(796×796-204×204)=?
-
592000
592001
582762
783623
4.(87×87+61×61-2×87×61)=?
-
295
562
195
196
5. What is the Unit Digit of 7105 ?
-
1
5
7
9
6.Which one of the following is not a prime number?
|
-
31
61
91
87
7.(112 x 54) = ? |
- 77000
70000
82444
77733
8.What least number must be added to 1056, so that the sum is completely divisible by 23 ?
|
-
3
5
6
2
9. 1397 x 1397 = ?
-
1951609.
1951611
1826351
3682251
10. How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
-
8
4
6
5
Show me the answers!
Question 1: The correct answer is the
Answer is A)
Unit Digit in the given product=Unit Digit in(4×8×7×3)=2
Answer is A)
Unit Digit in the given product=Unit Digit in(4×8×7×3)=2
Question 2: The correct answer is
Answer is B)
9587-X=7429-4358 then X=?
then 9887-X=3071
X=9587-3071=6516
Question 3: The correct answer is
Answer is C)
By Using this formula-(a²-b²)=(a+b)(a-b)
796×796-204×204=(796)²-(204)²
=(796+204)(796-204)=1000×593=592000
Answer is C)
By Using this formula-(a²-b²)=(a+b)(a-b)
796×796-204×204=(796)²-(204)²
=(796+204)(796-204)=1000×593=592000
Question 4: The correct answer is
Answer is D)
By Using the fomula-(a²+b²-2ab)=(a-b)²
where a=87,b=61
(87²+61²-2×81×61)=(87-61)²=(26)²=(20+6)²
=20²+6²-2x20x6=(400+36-240)
=(436-240)=196.
Answer is D)
By Using the fomula-(a²+b²-2ab)=(a-b)²
where a=87,b=61
(87²+61²-2×81×61)=(87-61)²=(26)²=(20+6)²
=20²+6²-2x20x6=(400+36-240)
=(436-240)=196.
Question 5: The correct answer is
Answer is C)
the Unit Digit of 7105 =Unit Digit in [(74)26×7]
The Unit Digit in (74)26=1
then Unit Digit in 7105 =(1x7)=7
Answer is C)
the Unit Digit of 7105 =Unit Digit in [(74)26×7]
The Unit Digit in (74)26=1
then Unit Digit in 7105 =(1x7)=7
Question 6: The correct answer is
Answer is C)
91 is divisible by 7. So, it is not a prime number
Answer is C)
91 is divisible by 7. So, it is not a prime number
Question 7: The correct answer is
Answer is B)
(112 x 54) = 112 x
10/2
4=112 x 104/16=1120000/6= 70000
Answer is B)
(112 x 54) = 112 x


Question 8: The correct answer is
Answer is D)
Answer is D)
Question 9: The correct answer is
Answer is A)
Question 10: The correct answer is
Answer is A)
1397 x 1397 | = (1397)2 |
= (1400 - 3)2 | |
= (1400)2 + (3)2 - (2 x 1400 x 3) | |
= 1960000 + 9 - 8400 | |
= 1960009 - 8400 | |
= 1951609. |
Answer is B)
132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264
11,3,4 (/)

396
11,3,4 (/)

462
11,3 (X)

792
11,3,4 (/)

968
11,4 (X)

2178
11,3 (X)

5184
3,4 (X)

6336
11,3,4 (/)

Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
You answered them all right!
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